4x^2+280x-4800=3

Solution for 4x^2+280x-4800=3 equation:

4x^2+280x-4800=3

We move all terms to the left:

4x^2+280x-4800-(3)=0

We add all the numbers together, and all the variables

4x^2+280x-4803=0

a = 4; b = 280; c = -4803;
Δ = b2-4ac
Δ = 2802-4·4·(-4803)
Δ = 155248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{155248}=\sqrt{16*9703}=\sqrt{16}*\sqrt{9703}=4\sqrt{9703}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(280)-4\sqrt{9703}}{2*4}=\frac{-280-4\sqrt{9703}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(280)+4\sqrt{9703}}{2*4}=\frac{-280+4\sqrt{9703}}{8}
$